B = {x : x²-5x+6 = 0, x belongs to N}
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ANSWER ::
B = {x : x²-5x+6 = 0, x belongs to N}
= { 2, 3 }
Since 2 & 3 are the zeros of the equation x²-5x+6 = 0
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x²-5x+6 = 0
=>x²-3x-2x+6 =0
=>x(x-3)-2(x-3)=0
=>(x-3)(x-2)=0=>x=2,3
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