Question

b. x² + 2x - 8 = 0 solve the following equations:​

Answer 1

$\sf{x^2 −2x−8=0}$

$\sf{x^2 −4x+2x−8=0}$

$\sf{x(x−4)+2(x−4)=0}$

$\sf{(x+2)(x−4)=0}$

$\implies \boxed{\sf{ \orange{ x=−2,4}}}$

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Hope it helps uh :)

Answer 2

Answer:

$\Huge \underline {\red {\bf{Answer}}}$

x ^ 2 − 2 x − 8 = 0

x ^ 2 − 4 x + 2 x − 8 = 0

x ( x − 4 ) + 2 ( x − 4 ) = 0

( x + 2 ) ( x − 4 ) = 0

⟹ x = − 2 , 4