Question

b) (x² + 2x² + 3x) = 2x​

Answer 1

${x}^{2} + 2 {x}^{2} + 3x = 2x$

$3 {x}^{2} + x = 0$

$x(3x + 1) = 0$

So,

$\boxed{x = 0}$

$3x + 1 = 0 \\ \boxed{x = \dfrac{ - 1}{3}}$

Answer 2

Answer:

ans is x=-1/3

Step-by-step explanation:

$( {x}^{2} + 2 {x}^{2} + 3x) = 2x \\ in \: the \: eq. \: xis \: common \\ (x + 2x + 3)x = 2x \\ 3x + 3 = 2 \\ 3x = 2 - 3 \\ x = - 1 \3 \: ans$

follow