Question

B1 B2 and B3 are three identical bulb connected in parallel through a battery of 4.5V and net current is flowing in the circuit is 3A
1. Draw a circuit diagram A.TO.Q
2. Find out the value of resistance of each bulb
3. If B2 bulb is fused in the given circuit then what amount of current wil flow through remaining bulb B1 & B3

Answer 1

2.V=IR
total resistance of the circuit=V/I=1.5 ohm
value of each resistance=1.5×3=4.5ohm as they are connected in parallel.
3. The amount of current flowing through each=I×R1/R1+R3=1.5A hope so