Question

B1,b2,b3 are three identical bulbs connected in parellel .when all bulbs glow a current of 3A is recorded by ammeter A. 1) what happens to the glow of other 2 bulbs when bulb bi is fused? 2) what happens to the reading of A1, A2 ,A3 and A WHEN THE BULB b2 GETS FUSED? 3) find out the total resistance of the circuit

Answer 1

1. the glow of the bulbs B2 and B3 will remain the same as the V and R remains the same.
2. When bulb 2 gets fused:
 Reading on A1 is 1 ampere, reading on A2 is 0 ampere, reading on A3 1  ampere and reading on A is 2 ampere.
3. Assuming the voltage being V the resistance of the circuit is:
 R=V/I=V/3
 

Answer 2

Current in ammeter A1 = 1 A

Current in ammeter A2 = 0

Current in ammeter A3 = 1 A

Current in ammeter A4 = 2A

Explanation:

(i) When bulb B1 will get fused, the currents in B2 and B3 are still same I2 = I3 = 1A.

Therefore, the glow of these bulbs will not be affected

(ii) When bulb B2 gets fused, the current in .B2 turns to be zero and currents in B1 and B3 remains 1 A.

therefore, Total current I = I1 + I2 + I3

= I + 0 + I = 2A

Current in ammeter A1 = 1 A

Current in ammeter A2 = 0

Current in ammeter A3 = 1 A

Current in ammeter A4 = 2A

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