Question

B²+ 100B - 200000=0​

Answer 1

Step-by-step explanation:

b^2+100b=200000

We move all terms to the left:

b^2+100b-(200000)=0

a = 1; b = 100; c = -200000;

Δ = b2-4ac

Δ = 1002-4·1·(-200000)

Δ = 810000

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

b1=−b−Δ√2a

b2=−b+Δ√2a

Δ−−√=810000−−−−−−−√=900

b1=−b−Δ√2a=−(100)−9002∗1=−10002=−500

b2=−b+Δ√2a=−(100)+9002∗1=8002=400

Answer 2

Answer:

B=400,-500

Step-by-step explanation:

B²+100B-200000=0

B²+500B-400B-200000=0 (factorisation)

B(B+500)-400(B+500)=0

(B-400)(B+500)=0

B-400=0. B+500=0

B=400. B=-500