Question

b²+5b+4=0 using square method​

Answer 1

Answer:

${b}^{2} + 5b + 4 = 0$

${b}^{2} + 5b + 4 + { (\frac{5}{2} )}^{2} - { (\frac{5}{2} )}^{2} = 0$

from here u can solve if u r not then let me know

Answer 2

Step-by-step explanation:

b² + 5b + 4

= b² + 2 × 5/2 × b + (5/2)² - 9/4

= (b+5/2)² - (3/2)²

= (b +5/2+3/2)(b+5/2-3/2)

=(b+4)(b+1)