Question

b²-9(b-1)²,if b =1.1

Answer 1

=b^2-9(b-1)^2
=b^2-9(b^2-2b+1)
=b^2-9b^2-18b-9
=-8b^2-18b-9
=8b^2+18b+9
=8b^2+36b-18b+9
=8(1.1)^2+36(1.1)-18(1.1)+9
=8(1.21)+39.6-19.8+9
=9.68+19.8+9
=38.48

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