b²/√a²+b² + a
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Answer:
root (a^2 + b^2) - a
Step-by-step explanation:
First multiply the numerator and denominator by root (a^2 + b^2) - a
Then by multiplying in denominator by identity a^2-b^2 = (a+b)(a-b)
now in denominator we get a^2+b^2-a^2
and in numerator b^2[root (a^2 + b^2) - a]
so by cancelling we get root (a^2 + b^2) - a
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