Question

B2) Alima has 76 coins, a mix of 50 p and 25 p. Find their numbers if the total money she has is 129.​

Answer 1

Answer:

Hey there!

For your question, let's assume there are "x" number of 50 p coins and "y" number of 25 p coins.

Hence,

x + y = 76x+y=76

Thus Total Money =

0.5x + 0.25y0.5x+0.25y

Since 50p = Rs 0.5 and 25p = Rs 0.25

But we have been given that the total money Alima has is Rs 29. Hence:

\begin{gathered}0.5x + 0.25y = 29 \\ \frac{x}{2} + \frac{y}{4} = 29 \\ \frac{1}{4}(2x + y) = 29 \\2x + y = 116 \\ x + ( x+ y) = 116\end{gathered}

0.5x+0.25y=29

2

x

+

4

y

=29

4

1

(2x+y)=29

2x+y=116

x+(x+y)=116

Here we know that (X + Y) is equal to 76, from the above equation, so we substitute it in this equation.

\begin{gathered}x + 76 = 116\\ x = 116 - 76 \\ x = 40\end{gathered}

x+76=116

x=116−76

x=40

Now we find the value of Y, using the first equation:

\begin{gathered}x + y = 76 \\ 40 + y = 76 \\ y = 76 - 40 \\ y = 36\end{gathered}

x+y=76

40+y=76

y=76−40

y=36

Hence X = 40 and Y = 36.

Thus Alima has forty 50p coins and thirty-six 25p coins

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Answer 2

Answer:

She has 40 50p coins and 36 25p coins

Step-by-step explanation:

Let her have x 50p coins and 76 - x 25p coins.

ATQ,

50x + 25(76 - x) = 12900 (because she has 29 RS.)

=> 50x - 25x + 1900 = 2900

=> 25x = 1000

=> x = 40

=> She has 40 50p coins and 36 25p coins

Hope it helps :)

Please mark brainliest if it does