Math, asked by avinash500200, 1 year ago

B2CD, _____, BCD4, B5CD, BC6D ????​

Answers

Answered by shrinivasnavindgikar
3

Answer:

Step-by-step explanation:

In this series, BCD is constant and numbers in sequence are inserted at second, third and fourth places respectively.. the numbers start from 2.... So the missing term would be BC3D

Please thank and mark brainliest

Answered by Anonymous
18

\huge\underline\red{\boxed{\boxed{BC3D}}}

\tt\underline\pink{Explanation:}

  • BCD is constant in every step.
  • The numbers are in sequence from 2 to 6.
  • The number 3 missing, so it should have 3 in it.
  • The numbers are placed in sequence at second,third and fourth position.
  • Since, in B2CD , the number is placed at second and in BCD4 , tge number is pkaced at fourth position.
  • The number in second step should be at third position.

So, the right answer is BC3D

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