Question

B2E,D5H,F12k,H27N,__________?

Answer 1

Given : B2E , D5H , F12K , H27N , ....

To find : The next term of the given series.

solution : Question is based on logical reasoning, series .

you can solve it easily when you get the relation between terms.

let's try to solve it.

here series is ; B2E , D5H , F12K , H27N

have a look bold and underlined letters of series.

B ⇒+2 ⇒D ⇒+2 ⇒F⇒+2⇒H

so, first letter of next term is H ⇒+2 ⇒J

now check, 2 , 5 , 12 , 27

here, 2 × 2 + 1 = 5

5 × 2 + 2 = 12

12 × 2 + 3 = 27

so, 27 × 2 + 4 = 54 + 4 = 58

finally observe on these letters ; E , H, K, N

E ⇒+ 3 ⇒H⇒+3 ⇒K⇒+3 ⇒N⇒ +3⇒Q

So the next term will be H58Q

Therefore next term of given series is H58Q

Answer 2

Answer:

Step-by-step explanation:

B2E, D5H ,F12K, H27N, J58Q

1-    B + 2 = D, D + 2 = F, F +2 = H, H + 2 = J

2-   2 × 2 + 1 = 5

     5 × 2 + 2 = 12

     12 × 2 + 3 = 27

      27 × 2 + 4 = 54 + 4 = 58

3-   E + 3 = H, H + 3 = K, K + 3 = N, N + 3 = Q

Therefore - J58Q is the answer.