Question

b²x/a -a²y/b=ab(a+b) and b²c-a²y=2a²b² solve for x and y by cross multiplication method

Answer 1

Answer:

By cross multiplying Equation 1:

= ((b^3)x-(a^3)y)/ab = ab(a+b)

= ((b^3)x-(a^3)y) = (a^2)(b^2)(a+b)

Equation 2 :

= (b^2)x - (a^2)y = 2(a^2)(b^2)

Dividing Equation 1 by Equation 2 :

=> (b^2+a^2+ab)/(a+b) = (a+b)/2

=> 2(b^2+a^2+ab) = (b^2+a^2+2ab)

=> b^2 + a^2 = 0

Since a^2 and b^2 are positive numbers thus if their sum is zero hence : a=b=0

So Solution set of x and y are all values.

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Answer 2

Step-by-step explanation:

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