Question

BA//ED AND BC//EF. PROVE THAT ANGLE ABC=ANGLE DEF

Answer 1

Answer:Given BA || ED and BC || EF.

To show ∠ABC = ∠DEF.

Construction Draw a ray EP opposite to ray ED.

Step-by-step explanation:

Answer 2

Answer

DE intersect BC at P

EF||BC & DP is transversal

∠ DEF = ∠ DPC . . . . . . . . ( i )

Now, AB||DP & BC is transversal

∠ DPC = ∠ ABC . . . . . . . ( ii )

From ( i ) & ( ii ),

we get :

∠ ABC = ∠ DEF

Hence , proved