Question

BA||ED and BC|| EF .show that angle ABC = angle DEF

Answer 1

Answer:

dear , please show diagram ...

Answer 2

Answer

DE intersect BC at P

EF||BC & DP is transversal

∠ DEF = ∠ DPC . . . . . . . . ( i )

Now, AB||DP & BC is transversal

∠ DPC = ∠ ABC . . . . . . . ( ii )

From ( i ) & ( ii ),

we get :

∠ ABC = ∠ DEF

Hence , proved