Question

BA is parpendicular to AC and DA is parpendicular to Df such that BA=DE and BF = EC. Prove that triangleABC is congruent to triangleDEF

Answer 1

Answer:

Given BA=DE

BF=EC

to prove: triangle ABC congruent to triangle DEF

Proof: BF=EC(given)

adding FC to both sides we get

BF+FC=EC+FC

BC=EF-------(i)

so in triangles ABC & DEF

AB= DE(given)

BC=EF(from (i) angle BAC= Angle FDE (both 90°)

so triangle ABC Is congruent to triangle DEF (RHS congruency)

Step-by-step explanation:

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