BA x BA =44A
plss give it's answer tomorrow is my exam
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Answer:
Given BA*B3=57A
taking common as B from given equation then B(3A)=57A
then B=57A/3A=19
Hence B=19
By substituting the value of B in given equation you will get the value of A is 1
Hence A=1,B=19
Verify it if you want.
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