Ba3(PO4)2 mein P ki oxidation number kya hogi ?
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P in Ba3(PO4)2 has an oxidation no. of 5.
Ba is +2, O is -2. the compound itself is neutral and if we take P's oxidation state as X then
2×3 + (X-4×2)×2 = 0
6 + 2X - 16 = 0
2X = 10
X = 5
Hence the oxidation state is +5
Ba is +2, O is -2. the compound itself is neutral and if we take P's oxidation state as X then
2×3 + (X-4×2)×2 = 0
6 + 2X - 16 = 0
2X = 10
X = 5
Hence the oxidation state is +5
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