∠BAC = 30 °, ∠ABC is = 50° and ∠CDE = 25°. Find ∠AED.
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Answer:
For triangle ACB
50°+ 30°= 80°
= 180°- 80°= 100°
For triangle ACB
= 180 -100= 80°
For triangle CED
= 180° -(80° +25°)
=180°-105
=75°
For triangle AED
= 180-75°
= 105°
For triangle AED(reflex)
= 180°+75°
= 255°
Step-by-step explanation:
I guess it is the correct answer
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