Question

bacl2+ h2so4. baso4 + hcl calculate the vol of hcl required when 416 gms of bacl2 is used​

Answer 1

Answer:

196g

Explanation:

Balanced equation is

$BaCl_{2} + H_{2}SO_{4} --> BaSO_{4} + 2HCl$

So, we know that one mole of BaCl2 reacts with one mole of H2SO4

416grams of BaCl2 consists of 2 moles.

Therefore the same amount of HCl must be used i.e. 2 moles

                                                        = 2 x (98)

                                                        = 196g

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