Question

Bacl2+kso4+-Baso4+kcl balance

Answer 1

Question:

Balance: BaCl₂ + K₂SO₄ = BaSO₄ + KCl

Answer:

Potassium sulphate formula is K₂SO₄ and not KSO₄ as the valency of SO₄ is 2- and not 1-.

To balance any equation, just follow the following steps.

Step 1: Write the equation as it is to avoid any confusion.

BaCl₂ + K₂SO₄ = BaSO₄ + KCl

Step 2: Make a table as shown. Write the symbol of elements, proportion of that element on L.H.S and R.H.S.

$\begin{array}{|c|c|c|} \cline{1-3} Elements & L.H.S & R.H.S \\ \cline{1-3} Ba & 1 & 1 \\ \cline{1-3} Cl & 2 & 1 \\ \cline{1-3} K & 2 & 1 \\ \cline{1-3} S & 1 & 1 \\ \cline{1-3} O & 4 & 4 \\ \cline{1-3} \end{array}$

Here, we can see that, K and Cl are not equal on either sides. So, we've to multiply with a suitable number by which they can be equalised.

Step 3: Multiplying 2 with K on R.H.S.

$\begin{array}{|c|c|c|} \cline{1-3} Elements & L.H.S & R.H.S \\ \cline{1-3} Ba & 1 & 1 \\ \cline{1-3} Cl & 2 & 1 \\ \cline{1-3} K & 2 & 1 \times 2 \\ \cline{1-3} S & 1 & 1 \\ \cline{1-3} O & 4 & 4 \\ \cline{1-3} \end{array}$

So, the elements becomes same as shown below:

$\begin{array}{|c|c|c|} \cline{1-3} Elements & L.H.S & R.H.S \\ \cline{1-3} Ba & 1 & 1 \\ \cline{1-3} Cl & 2 & 2 \\ \cline{1-3} K & 2 & 2 \\ \cline{1-3} S & 1 & 1 \\ \cline{1-3} O & 4 & 4 \\ \cline{1-3} \end{array}$

So, we've multiplied 2 on R.H.S so, all the elements become same. So, it means that this equation is balanced.

So, we've to write 2 as a co - efficient of K on R.H.S.

Then the equation becomes as:

$\boxed{\bold{BaCl_{2} + K_{2} SO_{4} \rightarrow BaSO_{4} + 2KCl}}$

If the equation is not balanced in step 3, then again follow the same procedure.

Answer 2

Answer:

Bacl2+k2So4=>BaSo4+2Kcl

Explanation:

Hence balanced

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