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Answer:
ab⁴ this is an answer
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Answer:
We have,
tanθ=
x
a
Since,
a
2
+x
2
x
⇒
a
2
+(
tanθ
a
)
2
tanθ
a
⇒
a
2
+
tan
2
θ
a
2
tanθ
a
⇒
a
tan
2
θ
1+tan
2
θ
tanθ
a
⇒
tan
2
θ
1+tan
2
θ
tanθ
1
⇒
sec
2
θ
1
⇒
secθ
1
⇒cosθ
Hence, this is the answer.
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