Question

bag 1 contains 5 black 5 red balls and bag 2 contain 4 black ball and 6 red balls and bag 3 contains 7 black and 3 red balls​

Answer 1

Step-by-step explanation:

Let E

1

,E

2

be the event of choosing bag 1 and bag 2 respectively.

E be the event that the drawn ball is red.

Then,

P(E

1

)=P(E

2

)=

2

1

P(E/E

1

)=

7

3

P(E/E

2

)=

11

5

ApplytheBayestheorem

P(E

2

/E

1

)=

2

1

×

7

3

+

2

1

×

11

5

2

1

×

11

5

=

68

35