Question

bag a contains 5 white and 6 black balls bag B contains 4 white and 3 black balls A ball is transferred from bag 82 bag B then A ball is taken out from bagby find the probability that the ball is a black ball

Answer 1

1. P(black ball from bag A)= 6/(5+6) = 6/11
similarly,
2. P(white ball from bag A)= 5/11
Now, If black ball was transferred from A to B:
3. P(Black ball from bag B)= (3+1)/(4+3+1) = 4/8
Now, If white ball was transferred from A to B:
4. P(Black Ball from bag B)= (3+0)/(4+3+1) = 3/8

5. P( Black ball from A & Black ball from B) = (6/11)×(4/8) = 3/11
6. P( white ball from A & Black ball from B) =
(5/11)×(3/8)= 15/88

7. P( Black ball from B after a ball is transferred from A) = (3/11) + (15/88)
= 39/88
ans.