Question

bag a contains 6 red and 4 blue balls. bag b contains 4 red and 6 blue balls. one ball is drawn at random from bag a and placed in bag b. then one ball drawn at random from bag b is placed in bag a. if one ball is now drawn from bag a, what is the probability that it is found to be red?

Answer 1

Well, for starters, bag A has 6/10 probability of being red, and a 4/10 prob. to be blue. The opposite is said for bag b. If we move on of the marbles from bag a to bag B to bag A, and do the opposite, then the probability for bag B being red should be multiplied by the probability of bag A being red (I think). It would look like 6/10 * 4/10, which would be 24/100. That SHOULD be the probability; hope it is and hope it helps!