Math, asked by nishalakra7032, 8 months ago

Bag A contains 'P green and 18 yellow balls while bag B contains (P+2) green balls and 22 more number of yellow balls than that of in bag A. Probability of selecting a green ball from bag A is 1/12 more than probability of selecting a green ball from bag B. Find total number of balls in bag B. ( P 50)

Answers

Answered by shanmukha2006ch
3

Answer:

22

Step-by-step explanation:

22

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Answered by smithasijotsl
0

Answer:

The number of balls in bag B is 240 or 48

Step-by-step explanation:

We know,

Probability of an event = Number of favorable outcomes/ Total number of outcomes

Given,

Bag A contains 'P' green and 18 yellow balls

Bag B contains  'P+2' green  and  18+22 yellow balls

Probability of selecting a green ball from bag A= \frac{1}{12} + probability of selecting a green ball from bag B

Required to find the total number of balls in Bag B

total number of balls in Bag B = P+2 +18+22 = P+42

Let P_1 and P_2 be the probability of selecting green balls from Bag A and Bag B respectively

Then

Then, P_1  = P_2 + \frac{1}{12}  ----------------------(1)

Probability of selecting a green ball from bag A = P_1 =

\frac{no. of green balls in bag A}{Total no. of balls in bag A}  = \frac{P}{P+18}

Probability of selecting a green ball from bag B = P_2 =

\frac{no. of green balls in bag B}{Total no. of balls in bag B}  = \frac{P+2}{P+2+18+22} = \frac{P+2}{P+42}

Substituting the value of P_1 and P_2 in equation (1)

\frac{P}{P + 18}  = \frac{1}{12}  + \frac{P+2}{P +42}

LCM =  12(P+42)

\frac{P}{P + 18}  = \frac{P+42 + 12(P +2)}{12(P+42)}

\frac{P}{P + 18}  = \frac{13P+66 }{12P+504}

P(12P+504) = (13P+66)(P+18)

12P^{2} + 504 P = 13P^2 + 234P +66P + 1188\\

Rearranging we get,

P^2 - 204 P +1188 = 0

To factorize the above equation we need to find two numbers such that Sum = -204 and Product 1188

Two such numbers are (-198) and (-6)

Then we have,

P^2 - 198 P - 6P +1188 = 0

(P-198)(P - 6) = 0

P = 198 or P = 6

Then Total number of balls in Bag B = P+42 = 198 +42 OR 6+42

= 240 OR 48

Hence Total number of balls in Bag B = 240 or 48

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