Bag A contains 'P green and 18 yellow balls while bag B contains (P+2) green balls and 22 more number of yellow balls than that of in bag A. Probability of selecting a green ball from bag A is 1/12 more than probability of selecting a green ball from bag B. Find total number of balls in bag B. ( P 50)
Answers
Answer:
22
Step-by-step explanation:
22
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Answer:
The number of balls in bag B is 240 or 48
Step-by-step explanation:
We know,
Probability of an event = Number of favorable outcomes/ Total number of outcomes
Given,
Bag A contains 'P' green and 18 yellow balls
Bag B contains 'P+2' green and 18+22 yellow balls
Probability of selecting a green ball from bag A= + probability of selecting a green ball from bag B
Required to find the total number of balls in Bag B
total number of balls in Bag B = P+2 +18+22 = P+42
Let and be the probability of selecting green balls from Bag A and Bag B respectively
Then
Then, = + ----------------------(1)
Probability of selecting a green ball from bag A = =
Probability of selecting a green ball from bag B = =
Substituting the value of and in equation (1)
LCM = 12(P+42)
P(12P+504) = (13P+66)(P+18)
Rearranging we get,
To factorize the above equation we need to find two numbers such that Sum = -204 and Product 1188
Two such numbers are (-198) and (-6)
Then we have,
(P-198)(P - 6) = 0
P = 198 or P = 6
Then Total number of balls in Bag B = P+42 = 198 +42 OR 6+42
= 240 OR 48
Hence Total number of balls in Bag B = 240 or 48