Question

bag contains 10 red, 5 blue and 7 green balls. A ball is drawn at random. Find the
obability of this ball being a
red ball
(ii) green ball
(ii) not a blue ball​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

(i) Total number of balls = 10+5+7 = 22.

 Red balls = 10

So,probability of drawing red balls = 10/22 = 0.45

(ii) Green balls = 7

Probability of drawing a green ball = 7/22 = 0.31

(iii) Blue balls = 5

Not a blue ball = 22-5 = 17

Therefore,probability of drawing not a blue ball = 17/22 = 0.77.