bag contains 10 white and 3 black balls.
Balls are drawn one by one without
replacement till all the black balls are
drawn. Find the probability that all black
balls are drawn by the 6thdraw.
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Total no: of balls = 13
probablity of drawing a white ball in 1st draw is 10/13
white ball in the 2nd draw is 9/12
white ball in the 3rd draw is 8/11
a black ball in 4th draw is 3/10
a black ball in the 5th draw is 2/9
a black ball in the 6th draw is 1/8
Therefore the required probablity is 10/13 x 9/12 x 8/11 x 3/10 x 2/9 x 1/8 = 4320/1235520 = 432/123552
probablity of drawing a white ball in 1st draw is 10/13
white ball in the 2nd draw is 9/12
white ball in the 3rd draw is 8/11
a black ball in 4th draw is 3/10
a black ball in the 5th draw is 2/9
a black ball in the 6th draw is 1/8
Therefore the required probablity is 10/13 x 9/12 x 8/11 x 3/10 x 2/9 x 1/8 = 4320/1235520 = 432/123552
mistisonai110p7w3di:
((3c2 * 10c3)/13c5)*1/8 is wrong?????
ji nhi
Mane jo calculation apko send kiya uska result apki result se alag an so konsa thik hai???plz ans
sorry ......lakin mari toh yahi answer ha
Apkihi ans thik hai sayed ok thank you
welcome
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