Question

Bag contains 1100 tickets numbered 1, 2, 3, ... 1100. if a ticket is drawn out of it at random, what is the probability that the ticket drawn has the digit 2 appearing on it

Answer 1

the probability is 2 upon 1100

Answer 2

Answer:

The probability that the ticket drawn has the digit 2 appearing on it is $\frac{29}{110}$.

Step-by-step explanation:

Given : Bag contains 1100 tickets numbered 1, 2, 3, ... 1100. if a ticket is drawn out of it at random.

To find : What is the probability that the ticket drawn has the digit 2 appearing on it?

Solution :

Total number of tickets in the bag n(s) = 1100.

Let A be the event of drawing a card of having 2 as a digit.

(1) Number of times 2 appears in 1 - 100= 19 (20,29,2,12,32,42,52,62,72,82,92)

(2) Number of times 2 appears in 101 - 200 = 20.

(3) Number of times 2 appears in 201 - 300 = 99

(4) Number of times 2 appears in 301 - 400 = 19

(5) Number of times 2 appears in 401 - 500 = 19

(6) Number of times 2 appears in 501 - 600 = 19

(7) Number of times 2 appears in 601 - 700 = 19

(8) Number of times 2 appears in 701 - 800 = 19

(9) Number of times 2 appears in 801 - 900 = 19

(10) Number of times 2 appears in 901 - 1000 = 19

(11) Number of times 2 appears in 1000 - 1100 = 19.

So, required number of ways n(A) :

⇒ 20 + 99 + 9(19)

⇒ 290

The required probability is

$P(A) = \frac{n(A)}{n(S)}$

$P(A) = \frac{290}{1100}$

$P(A) = \frac{29}{110}$

Therefore, The probability that the ticket drawn has the digit 2 appearing on it is $\frac{29}{110}$.