bag contains 4 green balls, 4 red balls, and 2 blue balls. If a ball is drawn from the bag, then what is the probability of getting neither green nor red ball? *
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Answer:
2/10 = 1/5
Step-by-step explanation:
so total no. of balls = 10
Neither green nor red ball means blue balls will be out
so probability of getting neither green nor red ball = no. of balls except green and blue balls/ total no. of balls
= 2/10 = 1/5
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