Bag contains 4 white, 7 black and 5 red balls. 4 balls are drawn with replacement. show that the probability of at least two balls are white is 6725667256.*
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yellow solution ok it's ok
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Answer: 67/256
Step-by-step explanation:
p=1/4 q=3/4 n=4
P(r)=4cr(1/4)^r(3/4)^n-r
Now required probability=1-P(x=0)-P(x=1)
=1-[81/256+27/64]
=67/256
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