Question

Bag contains 5 red and 3 green balls. another bag contains 4 red and 6 green balls. if one ball is drawn from each bag. find the probability that one ball is red and one is green.

Answer 1

First bag : Total = 5 + 3 = 8 balls

Second bag : Total = 4 + 6 = 10 balls

P(one red and one green) = (5/8) (6/10) + (3/8)(4/10) = 21/40

Answer: The probability is 21/40