Question

bag contains 7 red, 3 white and 5 blue balls. If ball is drawn at random from the bag, what is the probability of red​

Answer 1

Answer:

There are 15 balls (7 red, 5 blue & 3 green) in the bag from which 2 balls are picked up at random. Since, the balls are picked up at random, there cannot be any order like first draw, second draw etc. So, the number of ways 2 balls can be picked up is C(15,2)=105 . And the number of ways in which one red ball from 7 red balls and one blue ball from 5 blue balls can be drawn is C(7,1)∗C(5,1)=35 . Hence, the required probability is 35105=13

However, if the balls are picked up one by one without replacement then the required probability will be 715∗514=16 . Again, if the balls are picked up with replacement, then the required probability is 715∗515=745

Step-by-step explanation:

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Answer 2

Answer:

There are 15 balls (7 red, 5 blue

& 3 green) in the bag from which 2 balls are picked up at random. Since, the balls are picked up at random, there cannot be any order like first draw, second draw etc. So the number of ways 2 balls can be picked up is C(15,2)=105. And the number of ways in which one red ball from 7 red balls and one blue ball from 5 blue balls can be drawr is C(7,1)*C(5,1)=35. Hence, the required probability is 35105= 13

However, if the balls are picked up one by one without replacement then the required probability will be 715*514=16. Again, if the balls are picked up with replacement, then the required probability is 715*515-745

Step-by-step explanation:

I hope it's helps u

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