Bag i contains 1 white, 2 black and 3 red balls; bag ii contains 2 white, 1 black and 1 red balls; bag iii contains 4 white, 3 black and 2 red balls. A bag is chosen at random and two balls are drawn from it with replacement. They happen to be one white and one red. What is the probability that they came from bag iii.
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Probability of choosing bag iii = 1/3
Probability of 1 white ball and 1 red ball coming out of the bag iii = 1/9 x 1/9 = 1/81
∴Probability that one white and one red came from bag iii = 1/3 x 1/81 = 1/243.
Please check whether this is correct.
Sorry if it's wrong
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