Question

Bag I contains 5 red and 4 white balls. Bag Il contains 6 red and 8 white balls. Bag III contains 2 red and 6 white balls. A bag is selected at random and a ball is drawn from it, which is found to be white. Find the probability that ball is drawn from bag II.​

Answer 1

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

Bag 1 :-

• 5 red balls
• 4 white balls

Bag 2 :-

• 6 red balls
• 8 white balls

Bag 3 :-

• 2 red balls
• 6 white balls

Probability of white balls that are from bag 2 :-

FORMULA = $\tt \dfrac{FAVOURABLE \:O/C}{TOTAL \:NUMBER\: OF\: O/C}$

Total number of outcomes = 18

Favourable outcomes = 8

Answer :- $\tt \boxed {\dfrac {8}{18}}$

__________________

Answer 2

$\huge\underline\mathrm{Question-}$

Bag I contains 5 red and 4 white balls. Bag Il contains 6 red and 8 white balls. Bag III contains 2 red and 6 white balls. A bag is selected at random and a ball is drawn from it, which is found to be white. Find the probability that ball is drawn from bag II.

$\huge\underline\mathrm{Answer-}$

$\large{\boxed{\red{\rm{Probability\:that\:ball\:is\:drawn\:from\:bag\:II\:=\:\dfrac{8}{18}}}}}$

$\huge\underline\mathrm{Explanation-}$

It is given that :

• There are 5 red and 4 white balls in bag I.
• There are 6 red and 8 white balls in bag Il.
• There are 2 red and 6 white balls in bag Ill.

We have to find the probability that is drawn from bag Ii.

We know that,

$\huge{\boxed{\rm{P_{(e)}\:=\frac{Favourable\:Outcomes}{Total\:Outcomes}}}}$

Here, favourable outcomes = 8 ( As there are 8 white balls in bag Ii. )

Total outcomes = 18 ( as there are total 18 white balls )

$\large{\boxed{\red{\rm{\therefore\:Probability\:that\:ball\:is\:drawn\:from\:bag\:II\:=\:\dfrac{8}{18}}}}}$