Question

bag one contains 4 white balls and 3 green balls. Bag two contains 2 white balls and 4 green balls. A green ball is drawn from each bag. What is the probability it is from bag 1

Answer 1

$for \: bag \: 1 = \\ n(s) = 7 \\ n(a) = 3 \\ p(a) = \frac{n(a)}{n(s)} = \frac{3}{7} \\ for \: bag \: 2 = \\ n(s) = 6 \\ n(a) = 4 \\ p(a) = \frac{n(a)}{n(s)} = \frac{4}{6} = \frac{2}{3}$
$probality \: of \: bag \: 1 = \frac{3}{7}$