Question

bahi log

kal paper h iska answer

Answer 1

Answer:

Area of this triangle is $\dfrac{9\sqrt{3}}{4}$ cm^2

Step-by-step explanation:

It is given that the perimeter of the triangle( equilateral ) is 9 cm.

Let the side of the triangle be a cm,

From the properties of equilateral triangle, we know : -

Perimeter of equilateral triangle = 3 x side

Thus,

= >  3 x a cm = 9 cm

= >  a = 9 cm / 3 cm

= >  a = 3

Therefore, the length of each side of the equilateral triangle is 3 cm.

From the properties of equilateral triangle, we know : -

Area of equilateral triangle = $\dfrac{\sqrt{3}}{4}side^2$

Hence,

Area of this triangle = $\dfrac{\sqrt{3}}{4}\times (3cm)^2}$

Area of this triangle = $\dfrac{9\sqrt{3}}{4}$ cm^2