Math, asked by archanagupta01011990, 2 months ago

baichung father is 26 years younger than bacche grandfather and 29 years older than baichung the sum of age of all the three is 135 years what is the age of each one of them​

Answers

Answered by Ramya852007
0

Answer:

Age of Baichung is 17 years. Age of Baichung's father is x+29→17+29=46 years. Age of Baichung's Grandfather is x+29+26→17+29+26= 72 years.

Step-by-step explanation:

please mark me as brainlist

Answered by Anonymous
10

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}

\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}

A.T.Q :

\longmapsto\tt{x+x-26+x-55=135}

\longmapsto\tt{3x-81=135}

\longmapsto\tt{3x=135+81}

\longmapsto\tt{3x=216}

\longmapsto\tt{x=\cancel\dfrac{216}{3}}

\longmapsto\tt\bf{x=72}

Value of x is 72 .

Therefore :

\longmapsto\tt{Age\:of\:his\:Grandfather=x}

\longmapsto\tt\bf{72\:yrs}

\longmapsto\tt{Age\:of\:his\:Father=72-26}

\longmapsto\tt\bf{46\:yrs}

\longmapsto\tt{Age\:of\:Baichung=72-55}

\longmapsto\tt\bf{17\:yrs}

Similar questions