Math, asked by janvi5151, 9 months ago

Baichung father is 26 years younger than baichung grandfather and 29 years older than baichung the sum of the ages of all the 135 years what is the ages of each one of the m

Answers

Answered by sp1244
3

Answer:

Let the age of baichung's father be x

Age of baichung's grandfather = x+26

Age of baichung= x-29

According to the question

x+x+26+x-29= 135

3x-3=135

3x=138

x=46

Baichung's father age=46

Baichung's age=x-29= 46-29=17

Baichung's grandfather age= x+26=46+26= 72

Hey mate hope this answer helps you

Answered by XxxRAJxxX
0

Let the age of Baichung’s father be x.

Then, the age of Baichung’s grandfather = (x+26)

and, Age of Baichung = (x-29)

According to the question,

x + (x+26) + (x-29) = 135

⇒ 3x + 26 – 29 = 135

⇒ 3x – 3 = 135

⇒ 3x = 135 + 3

⇒ 3x = 138

⇒ x = 138/3

⇒ x = 46

Age of Baichung’s father = x = 46

Age of Baichung’s grandfather = (x+26) = 46 + 26 = 72

Age of Baichung = (x-29) = 46 – 29 = 17

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