Math, asked by me164333, 7 months ago

baichung father is 26 years younger than baichung grandfather and 29 older than b to the sum of the ages of all the three is 1 35 years what is the age of each one of them​

Answers

Answered by EnchantedGirl
8

Given:-

  • Baichung father is 26 years younger than baichung grandfather and 29 older than b to the sum of the ages of all the three is 135 years .

To find:-

  • what is the age of each one of them.

Solution:-

Let the age of Baichung be x years.

Then , age of father would be x + 29 years.

And  age of grandfather would be x + 29 + 26   = x + 55 years .

given that  sum of their ages =  135 years.

so,

=> x + x + 29 + x + 55 = 135

=> 3x + 84= 135

=> 3x = 135 - 84

=> 3x = 51

=> x = 51/3

=> x = 17

Therfore,

  • age of Baichung = 17 years

  • age of Baichung's father = 17 + 29 = 46 years

  • age of Baichung's grandfather = 17 + 55 = 72 years.

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Answered by Anonymous
5

Step-by-step explanation:

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