baichung father is 26 years younger than baichung grandfather and 29 older than b to the sum of the ages of all the three is 1 35 years what is the age of each one of them
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Given:-
- Baichung father is 26 years younger than baichung grandfather and 29 older than b to the sum of the ages of all the three is 135 years .
To find:-
- what is the age of each one of them.
Solution:-
Let the age of Baichung be x years.
Then , age of father would be x + 29 years.
And age of grandfather would be x + 29 + 26 = x + 55 years .
given that sum of their ages = 135 years.
so,
=> x + x + 29 + x + 55 = 135
=> 3x + 84= 135
=> 3x = 135 - 84
=> 3x = 51
=> x = 51/3
=> x = 17
Therfore,
- age of Baichung = 17 years
- age of Baichung's father = 17 + 29 = 46 years
- age of Baichung's grandfather = 17 + 55 = 72 years.
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