Question

baichung's father is 26 years older than baichung's grangfather and 29 years older than baichung.the sum of the ages of all the three is 135 years.what is the age of eachone of them

Answer 1

GIVEN :-

⇒Baichung ''s Father age   is 29 yrs older than baichungs grandfather  and 29 yrs older than Baichung

⇒The sum of all the three ages  =  135 yrs.

TO FIND ;-

⇒ What is the age of each one of them = ?

SOL ;-

⇒ We dont know the age of Baichung so let us take his age as x.

⇒  Baichungs fathers age = x + 29 yrs { because Baichungs father is 29 yrs                                                                elder than Baichung }

⇒Baichungs grandfather age = x + 29 + 26 {As Baichungs grandfather is                                                                          elder than Baichung and                                                                                 Baichungs son }

⇒ In the question  it is given that their sum of their ages is 135 yrs.

⇒So we get as ,

⇒ x    +  x  +   29  +  x  +  29  +  26  =  135  { Adding all  the ages }
           
3   x   +   84              =  135
                   
3x                             = 135  -   84
                    
3x                             =51
                     
x                               = 51/3

x                               = 17

⇒Hence x is 17 yrs

⇒Now apply the value of x

Baichungs age is 17 yrs

Baichungs fathers age is = 17 + 29 = 46 yrs

Baichungs grandfather age is = 17 + 29 + 26 + 72 yrs 

Hence we got the answer.

Answer 2

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Let the age of Baichung’s father = m year

Since, Baichung’s father is 26 year younger than Baichung’s grand father

Therefore, Age of Baichung’s grandfather = Age of Baichung’s father + 26 = m + 26 year

Since, Baichung’s father is 29 year older than Baichung

Therefore, Age of Baichung = Age of Baichung’s father – 29 = m – 29 year

Now, we have

Age of Baichung = m – 29 year

Age of Baichung’s father = m year

Age of Bahichung’s grandfather = m + 26 year

According to question, the sum of ages of all the three = 135 year

Therefore,

• Age of Baichung + Age of Baichung’s father + Age of Baichung’s grandfather = 135.

⇒ (m – 29) + m + (m + 26) = 135 year

⇒ m – 29 + m + m + 26 = 135 year

⇒ m + m + m – 29 + 26 = 135 year

⇒ 3m – 3 = 135 year

After transposing – 3 to the RHS, we get

3m = 135 year + 3

⇒ 3m = 138 year

After dividing both sides by 3, we get

This means age of Baichung’s father = 46 year

Now, by substituting the value of m, we can calculate the age of Baichung and the age of Baichun’s grandfather.

Therefore,

Age of Baichung = m – 29 = 46 – 29 = 17 year

Age of Baichung’s grandfather = m + 26 = 46 + 26 = 72 year

Thus,

• Age of Baichung = 17 year

• Age of Baichung’s father = 46 year

• Age of Baichung’s grandfather = 72 year

Hope it helps you!

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