Question

Baichung's father is 26 years younger than baichung's grandfather and 29 years older than baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Answer 1

Answer:

fathers age =46

grand father age= x+29=75

baichung age =x -26= 20

Step-by-step explanation:

baichung fathers age = x

grand father= x+26

baichung= x-29

total age = 135 yrs

x+x+26+x-29=135

3x-3=135

3x = 135+ 3

3x = 138

x= 138/3

x =46

Answer 2

Answer:

$\huge \mathbb \color{purple}{ANSWER \implies}$

Let the age of Baichung be x years.

The age of his father = x + 29 years,

and the age of his grandfather = x + 29 + 26 = (x + 55) years.

As per the conditions, we get

x + x + 29 + x + 55 = 135

⇒ 3x + 84 = 135

⇒ 3x = 135 – 84 (transposing 84 to RHS)

⇒ 3x = 51

⇒ x = 51 ÷ 3 (transposing 3 to RHS)

⇒ x = 17

Hence Baichung’s age = 17 years

Baichung’s father’s age = 17 + 29 = 46 years,

and grand father’s age = 46 + 26 = 72 years.

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