Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the ages of all three is 135 years. What is the age of each one of them
Answers
Answer:
Given Bf = Bg -26
Bf +26 = Bg .... (1)
given Bf = B +29
Bf -29 = B ..... (2)
given B+Bf+Bg= 135..... (3)
substitute 1 and 2 in 3 we get
(Bf -29)+(Bf)+(Bf+26) =135
3Bf -3 = 135
3Bf = 138
Bf = 46 years
now B = 17years and Bg = 72 years
Let the age of Baichung’s father = m year
Since, Baichung’s father is 26 year younger than Baichung’s grand father
Therefore, Age of Baichung’s grandfather = Age of Baichung’s father + 26 = m + 26 year
Since, Baichung’s father is 29 year older than Baichung
Therefore, Age of Baichung = Age of Baichung’s father – 29 = m – 29 year
Now, we have
Age of Baichung = m – 29 year
Age of Baichung’s father = m year
Age of Bahichung’s grandfather = m + 26 year
According to question, the sum of ages of all the three = 135 year
Therefore,
Age of Baichung + Age of Baichung’s father + Age of Baichung’s grandfather = 135
⇒ (m – 29) + m + (m + 26) = 135 year
⇒ m – 29 + m + m + 26 = 135 year
⇒ m + m + m – 29 + 26 = 135 year
⇒ 3m – 3 = 135 year
After transposing – 3 to the RHS, we get
3m = 135 year + 3
⇒ 3m = 138 year
After dividing both sides by 3, we get
This means age of Baichung’s father = 46 year
Now, by substituting the value of m, we can calculate the age of Baichung and the age of Baichun’s grandfather.
Therefore,
Age of Baichung = m – 29 = 46 – 29 = 17 year
Age of Baichung’s grandfather = m + 26 = 46 + 26 = 72 year
Thus,
Age of Baichung = 17 year
Age of Baichung’s father = 46 year
Age of Baichung’s grandfather = 72 year
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