Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135. What is the age of each one of them?
Answers
Answer:
Let the age of baichung's father be x
Then the age of baichung's grandfather=x+26
the age of baichung=x-29
According to question:
x+x+26+x-29=135
3x-3=135
3x=138
x=46
Age of baichung's father= 46
Age of baichung's grandfather= x+26 =46+26=72
Age of baichung=x-29=46-29=17
Step-by-step explanation:
Answer:
Step-by-step explanation:
Solution :-
Let the Baichung’s age be x years.
And Baichung’s father present age be y years.
And Baichung’s grandfather present age be z years.
According to the Question,
⇒ y = x + 29..…(i)
⇒ z = y + 26....(ii)
Putting Eq (i) in (ii), we get
⇒ z = x + 29 + 26
⇒ z = x + 55 ....(iii)
Sum of their ages = 135
⇒ x + y + z = 135
⇒ x + x + 29 + x + 55 = 135
⇒ 3x + 84 = 135
⇒ 3x = 135 - 84
⇒ 3x = 51
⇒ x = 51/3
⇒ x = 17
Baichung’s age = x = 17 years.
Baichung’s father's age = x + 29 = 17 + 29 = 46 years.
Baichung’s grandfather age = x + 55 = 17 + 55 = 72 years.