Math, asked by abhi958, 1 year ago

Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years what is the age of each one of them

Answers

Answered by Anonymous
655
Let the age of baichung's father be x
Then the age of baichung's grandfather=x+26
the age of baichung=x-29

According to question:
x+x+26+x-29=135
3x-3=135
3x=138
x=46

Age of baichung's father= 46
Age of baichung's grandfather= x+26 =46+26=72
Age of baichung=x-29=46-29=17

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abhi958: i will join you
Answered by locomaniac
234
aloha user!!
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let the age of Baichung be x years.
age of father would be x + 29 years.
age of grandfather would be x + 29 + 26
= x + 55 years

now sum of their ages is given to be 135 years.
so,
x + x + 29 + x + 55 = 135
3x + 84= 135
3x = 135 - 84
3x = 51
x = 51/3
x = 17

age of Baichung = 17 years
age of Baichung's father = 17 + 29 = 46 years
age of Baichung's grandfather = 17 + 55 = 72 years.

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peace out !!
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