baichung's father is 26 years younger than baichung's grandfather and 29 years older than baichung.the sum of the ages of all the three is 135 years.what is the age of eachone of them
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16
Let baichungs age be x
Age of his father =x+29
Age of his grandfather =(x+29)+26
ATQ,x+(x+29)+{(x+29)+26}=135
= 3x+29+29+26=135
=3x+84=135
=x=(135-84)/3
=17
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Answered by
9
Let the age of baichung be b years
his father's age is f
grandfather's age is g
A/q
f+26 =g___(1)
f-29 = b___(2)
adding (1) and (2).
b+g = 2f -3___(3)
and b+f+g = 135___(4)
substituting the value of (3) in (4)
f+2f-3 = 135
⇒3f = 138
⇒f =46 years
then g= f+26 = 46+26 = 72 years
and b = f-29 = 46 -29 =17 years
his father's age is f
grandfather's age is g
A/q
f+26 =g___(1)
f-29 = b___(2)
adding (1) and (2).
b+g = 2f -3___(3)
and b+f+g = 135___(4)
substituting the value of (3) in (4)
f+2f-3 = 135
⇒3f = 138
⇒f =46 years
then g= f+26 = 46+26 = 72 years
and b = f-29 = 46 -29 =17 years
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