Question

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

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Answer 1

Answer:

Let the age of baichung's father be 'x'.

Then the age of baichung's grandfather='x+26'.

The age of baichung='x-29'

According to question:

⇒x+x+26+x-29=135

⇒3x-3=135

⇒3x=138

⇒x=46

Age of baichung's father= $46$

Age of baichung's grandfather= $x+26 =46+26=72$

Age of baichung= $x-29=46-29=17$

Step-by-step explanation:

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Answer 2

Answer:

let the baichung's age be "x"years

Baichung's fathers age =x+29

Baichung's grand father's age =x+26+29

A. C. T. Q

x+x+29+x+26+29=135

=3x+55+29=135

3x+84=135

3x=135-84

3x=51

x=51/3

x=17

therefore, baichung's age =17 years, baichung's father's age =x+29=17+29=46 years and baichung's grand father's age =x+26+29 =17+26+29=72 years