Question

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung.
The sum of the ages of all the three is 135 years. What is the age of each one of them?

Answer 1

$Solution :$

Let the age of baichung's father be x

Then the age of baichung's grandfather=x+26

the age of baichung=x-29

According to question:

x+x+26+x-29=135

3x-3=135

3x=138

x=46

Age of baichung's father= 46

Age of baichung's grandfather= x+26 =46+26=72

Age of baichung=x-29=46-29=17

Answer 2

Step-by-step explanation:

Let Baichung’s age be x.

Given That:

Baichung's father age is older than Baichung's .

Baichung's father age = (x + 29) years

Also,

Baichung’s father is 26 years younger than Baichung’s grandfather.

Age of Baichung's father = Age of Baichung's grandfather - 26

Age of Baichung's Father + 26 = Age of Baichung's grandfather.

Age of Baichung's grandfather = Age of Baichung's father+ 26.

Age of Baichung's Grandfather = (x + 29) + 26

= ( x + 55) years

Given,

Sum of all the ages is 135.

x + (x +29) + (x+ 55) = 135

3x + 84= 135

3x = 135-84

3x = 51

x = 51

3

x = 17

: Baichung's age = x = 17 years

Baichung's Father age = x + 29 = 17 + 29 = 46 years

Baichung's GrandFather age = x + 55 = 17 + 55 = 72 years