Math, asked by ThePhenomenol, 5 hours ago

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?​

Answers

Answered by sunprince0000
1

Answer:Age of Baichung's Grandfather is x+26→46+26=72 years. Age of Baichung is 17 years. Age of Baichung's father is x+29→17+29=46 years.

Step-by-step explanation:

Answered by llXxMrSubanshxXll
377

 \color{skyblue} \large\underline{{\boxed{\sf\pink{Given:-}}}}

  • Baichung’s father is 26 years younger than Baichung’s grandfather.
  • Baichung father is 29 years older than Baichung.
  • Sum of their ages = 135

 \color{skyblue} \large\underline{{\boxed{\sf\red{To \: Find :-}}}}

  • The age of each one of them

 \color{skyblue} \large\underline{{\boxed{\sf\orange{Solution:-}}}}

  • Let the age of Baichung be x years.
  • The age of his father = x + 29 years.
  • The age of his grandfather = x + 29 + 26 = (x + 55 ) years.

According to the question

 \sf \mapsto \: x + x + 29 + x + 55 = 135

 \sf \mapsto \: 3x + 29 + 55 \:  = 135

 \sf \mapsto \: 3x + 84 = 135

 \sf \mapsto \: 3x = 135 - 84

 \sf \mapsto \: 3 x = 51

 \sf \mapsto \: x =  \frac{ \cancel{51}}{ \cancel3} = 17

 \sf \mapsto \: x = 17

Hence,

 { \underline { \boxed {\pink {\begin{array} {c}  \sf \: Baichung’s  \: age = 17 \:  years  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \sf \: Baichung’s \:  father’s  \: age = 17 + 29 = 46 \: years  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \sf \: Baichung’s  \: grandfather’s  \: age =46 + 26 = 72 \: years.  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \end{array}}}}}

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