Question

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them? (please don't copy paste)​

Answer 1

Given that:

• Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung.
• The sum of the ages of all the three is 135 years.

To Find:

• What is the age of each one of them?

Let us assume:

• Baichung’s age be x.
• Baichung’s father age = x + 29
• Baichung’s grandfather age = x + 29 + 26

Finding the age of each one of them:

According to the question.

⟶ x + x + 29 + x + 29 + 26 = 135

⟶ 3x + 84 = 135

⟶ 3x = 135 - 84

⟶ 3x = 51

⟶ x = 51/3

⟶ x = 17

Hence,

1. Baichung’s age = x = 17 years
2. Baichung’s father age = x + 29 = 17 + 29 = 46 years
3. Baichung’s grandfather age = x + 29 + 26 = 17 + 29 + 26 = 72 years

Answer 2

Given :-

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years.

To Find :-

Age of each

Solution :-

Let the age of Baichung be B

Age of father = B + 26

Age of grandfather = B + 26 + 29

Age of grandfather = B + 55

Now

(B) + (B + 26) + (B + 55) = 135

3B + 81 = 135

3B = 135 - 81

3B = 54

B = 54/3

B = 18

Now

Age of Baichung = 18 years

Age of his father = 18 + 26 = 44 years

Age of grandfather = 18 + 55 = 73 years

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